IPv6 addresses problem

IPv6 is proposed as an almost unlimited source of addresses to overcome the IPv4 address shortage some people have suggested. As IPv6 addresses are 128-bit long, 2^128 (aprox 3.4 x 10^38 ) addresses are possible. This should be large enough.

To put things into perspective consider the following problem: How many IPv6 addresses could you put into each squared centimeter of the planet? (Assume the Earth is a regular sphere of 40.000 Km of perimeter).

And a second part … compare the above number of IPv6 addresses per square centimeter to the total address space of IPv4.

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4 Comments

  1. Jose Manuel
    Posted February 26, 2009 at 5:33 pm | Permalink | Reply

    I think it´s around 6×10^20 IP Adresses per squared centimeter, more or less.

  2. Posted February 26, 2009 at 6:24 pm | Permalink | Reply

    I think José Manuel is quite close but you can do better. Don’t forget the second question either.Anybody else? Remember you can do math with Google too as in the < HREF="http://www.google.es/search?q=2%5E128&ie=utf-8&oe=utf-8&aq=t&" REL="nofollow">example<>

  3. José Manuel
    Posted February 26, 2009 at 8:48 pm | Permalink | Reply

    I think that i have already done a better aproximation. The total Adresses per squared centimeter it´s around: 6.67220327 × 10^20 adressesAnd in the second part:(6.67220327 × (10^20)) / (2^32) = 1.55349338 × 10^11 times more (respect of total space of Ipv4) Anyway, all these numbres are amazing!

  4. Posted February 26, 2009 at 11:03 pm | Permalink | Reply

    First question:(3.1416 * (2^128)) / (4e9^2) = 6.68144427 × 10^19Second one:((3.14 * (2^128)) / (4e9^2)) / (2^32) = 1.55485269 × 10^10or 15 billion times the IPv4 addressing space per each square centimeter of the planet surface, not bad isn’t it?

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